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cryptoracle_v1.md
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cryptoracle_v1.md
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# CryptOracle v1
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`CryptOracle v1` is an introductory cryptography and reverse engineering challenge that simulates a Hardware Security Module (HSM). The objective is to retrieve a secret flag stored in a "secure" memory region that is supposedly isolated from the user.
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## Information Gathering
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We are provided with a `cryptOracle_v1.tar.xz` archive containing the `crypt_oracle_v1` binary. Initial analysis confirms it is a statically linked 64-bit ELF executable.
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```bash
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$ file crypt_oracle_v1
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crypt_oracle_v1: ELF 64-bit LSB executable, x86-64, version 1 (SYSV), statically linked, ...
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```
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Upon connecting to the challenge server, we are greeted with the following interface:
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```
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CryptOracle v1.0
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Setting up memory...
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0x10000 - 0x11000 : Secure Memory (Keys/ROM)
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0x20000 - 0x28000 : User Memory
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Type 'help' for commands.
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```
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The challenge description hints that sensitive keys are stored at address `0x10000`.
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## Reverse Engineering
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We use Ghidra to analyze the binary and understand how it manages memory access.
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### 1. Main Interaction Loop (`main`)
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The `main` function initializes the HSM simulation and processes user commands.
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```c
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undefined8 main(void)
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{
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int iVar1;
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char *pcVar2;
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long in_FS_OFFSET;
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undefined4 local_428;
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undefined4 local_424;
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undefined4 local_420;
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undefined4 local_41c;
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char local_418 [512];
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undefined1 local_218 [520];
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long local_10;
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local_10 = *(long *)(in_FS_OFFSET + 0x28);
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setvbuf((FILE *)stdout,(char *)0x0,2,0);
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puts("CryptOracle v1.0");
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setup_memory();
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puts("Type \'help\' for commands.");
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while( true ) {
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pcVar2 = fgets(local_418,0x200,(FILE *)stdin);
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if (pcVar2 == (char *)0x0) break;
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iVar1 = strncmp(local_418,"rm",2);
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if (iVar1 == 0) {
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iVar1 = __isoc99_sscanf(local_418,"rm 0x%x %d",&local_420,&local_41c);
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if (iVar1 == 2) {
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do_read(local_420,local_41c);
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}
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}
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// ... (other commands) ...
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}
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// ...
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return 0;
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}
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```
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The `rm` command takes a hexadecimal address and a decimal size, then calls the `do_read` function.
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### 2. Memory Initialization (`setup_memory`)
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The `setup_memory` function reveals where the flag is placed.
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```c
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void setup_memory(void)
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{
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void *pvVar1;
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FILE *__stream;
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size_t sVar2;
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puts("Setting up memory...");
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pvVar1 = mmap64((void *)0x10000,0x1000,3,0x32,-1,0);
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// ...
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pvVar1 = mmap64((void *)0x20000,0x8000,3,0x32,-1,0);
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// ...
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memset((void *)0x10000,0,0x1000);
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memset((void *)0x20000,0,0x8000);
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__stream = fopen64("flag.bin","rb");
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if (__stream != (FILE *)0x0) {
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sVar2 = fread((void *)0x10000,1,0x800,__stream);
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fclose(__stream);
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// ...
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return;
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}
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// ...
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}
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```
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We confirm that the flag from `flag.bin` is loaded directly into the "Secure Memory" region at `0x10000`.
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### 3. Vulnerability Analysis (`get_ptr`)
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The `do_read` function calls a helper called `get_ptr` to validate memory access before printing data.
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```c
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void do_read(undefined4 param_1,undefined4 param_2)
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{
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long lVar1;
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lVar1 = get_ptr(param_1,param_2,0);
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if (lVar1 == 0) {
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puts("ERR_ACCESS_VIOLATION");
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}
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else {
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print_hex(lVar1,param_2);
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}
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return;
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}
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```
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Now let\'s examine the logic in `get_ptr`:
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```c
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uint get_ptr(uint param_1,int param_2,int param_3)
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{
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// 1. Integer overflow check: ensure address + size doesn't wrap around
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if (param_2 + param_1 < param_1) {
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param_1 = 0;
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}
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// 2. Range Validation: check if access is within mapped regions
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else if ((param_1 < 0x10000) || (0x11000 < param_2 + param_1)) {
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// If not in Secure Memory (0x10000-0x11000), check User Memory (0x20000-0x28000)
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if ((param_1 < 0x20000) || (0x28000 < param_2 + param_1)) {
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param_1 = 0;
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}
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}
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// 3. Security Check: block access to flag region (0x10000 - 0x10800)
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// This is ONLY enforced if param_3 (check_secure) is non-zero
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else if ((param_3 != 0) && (param_1 - 0x10000 < 0x800)) {
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param_1 = 0;
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}
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return param_1;
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}
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```
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The validation logic in `get_ptr` works as follows:
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1. **Integer Overflow**: It checks if `size + addr` overflows.
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2. **Range Validation**: It ensures the access is within the Secure Memory (`0x10000-0x11000`) or User Memory (`0x20000-0x28000`).
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3. **Secure Memory Restriction**: It explicitly blocks access to the first `0x800` bytes of Secure Memory (where the flag is stored) **ONLY IF** `param_3` (the `check_secure` flag) is non-zero.
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Crucially, in the `do_read` function (which implements the `rm` command), the third argument passed to `get_ptr` is **hardcoded to `0`**. This means the specific check that protects the secret keys is bypassed when using the "read memory" command.
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## Solution
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Because the `rm` command bypasses the isolation check in `get_ptr`, we can directly dump the secure RAM.
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1. Connect to the server.
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2. Read the memory at address `0x10000`.
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```bash
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> rm 0x10000 32
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00010000: 7b 66 6c 61 67 3a 20 74 68 61 74 5f 77 61 73 5f {flag: that_was_
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00010010: 74 6f 6f 5f 65 61 73 79 5f 72 69 67 68 74 3f 7d too_easy_right?}
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```
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The flag is revealed: `{flag: that_was_too_easy_right?}`
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```
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